this post was submitted on 20 May 2025
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[–] [email protected] 48 points 4 days ago (1 children)

The laser produced power? How do we harness that so we can power the world with lasers? 🤔

[–] [email protected] 23 points 3 days ago (1 children)

It's no different than an engine producing power. I think you are confusing it with "energy".

[–] [email protected] 3 points 3 days ago (2 children)

No the laser didn't produce anything the laser is powered by a power source, and that power source produced that much energy.

It's like saying that an ultrasonic saw produces power, no it doesn't, you already have to have that power to feed into the ultrasonic saw.

[–] [email protected] 13 points 3 days ago

The laser didn’t generate 2 quadrillion watts like a power plant would generate electricity, but it delivered that much power in an extremely short pulse, like 20 quadrillionths of a second.

That means the energy it delivered was relatively small (a few hundred joules), but because it was delivered in such a tiny time window, the power (which is energy per unit time) was immense.

The laser did produce power, in the form of intense light and heat, over a very small time period. It converted 2 quadrillion watts of electric energy into a very brief laser pulse.

[–] [email protected] 3 points 3 days ago

That's not strictly true.

Chemical lasers absolutely generate their own power, you're thinking of electro-optically excited lasers.

[–] [email protected] 22 points 4 days ago* (last edited 4 days ago) (3 children)

Edit 2: Eheran pointed out I screwed up the math. Correct total energy output is 13μWh. A very, very, very small amount of energy.

(2x10^15^ W) * (25s/1x10^18^) * (1 h/ 3600 s) = 13μWh


Previous bad math:

spoiler

~~The key thing here is the burst lasted for "25 quintillionths of a second long". Meaning it had a total output energy of 180 W/h, or how much energy a standard US space heater (1.5KW) outputs if it was on for 7.2 minutes.~~

~~That is a pretty impressive amount of power coming in instantly to a small spot. Would leave basically zero time for it to dissipate into surrounding materials.~~

~~Edit: Fixed the math. (I hope)~~ ~~(2x10^15^ W) * (25/1x10^18^ s) * (3600 s / 1 h) = 180W/h~~

[–] [email protected] 6 points 4 days ago (1 children)

You multiply seconds with seconds per hour and somehow get "per hour" as the final result? But even ignoring that error, what is W/h supposed to be? Rate of change of power?

[–] [email protected] 2 points 4 days ago (1 children)

You multiply seconds with seconds per hour and somehow get "per hour" as the final result? But even ignoring that error, what is W/h supposed to be? Rate of change of power?

Also, it is a small k for kilo and you don't write it as 4.310^18^[unit]. Just 4.310^18 [unit]. Or 4.3E18 [unit].

[–] [email protected] 2 points 4 days ago* (last edited 3 days ago)

Crap, you are right, units should be in Wh not W/h and as a result I put the conversion to hours backwards. Well, that turns the whole thing from an impressive amount of energy to basically none!

[–] [email protected] 4 points 4 days ago* (last edited 4 days ago)

That's 25 attoseconds, no?... If so, that's impressive.

The power record holder right now is the Măgurele laser in Romania, at 10 PW, but it lasts a thousand times longer, at 25 femtoseconds I believe. I can't find clear info on pulse duration anywhere. They do intend to decrease pulse durations it seems.

[–] [email protected] 2 points 3 days ago

could this boil one molecule of water?

[–] [email protected] 4 points 3 days ago

Aim it at Epstein island

[–] [email protected] 6 points 4 days ago* (last edited 4 days ago) (3 children)

I have a decent grasp of physics but I understand nothing at all about this article. Melp me out, please?

What use is a high energy beam that last for an almost immeasurably short period of time? How can it even be said that it has this power output, in such a short time?

"Zero-POW!-zero" sounds unbelievable to normal humans. No ramp-up? No sizzling out?

On such a short time scale, what's the actual Wh used? It can't be very much, so the actual energy delivered can hardly do anything at all, either.

And finally, what's even the point of this? What's the purpose? What's the end goal? Why?

many possible applications, including better imaging methods for soft tissues and advancing the technology used to treat cancer

I don't see how that works out.

Thank you for indulging me. I appreciate any responses.

[–] [email protected] 7 points 3 days ago

It has a lot of value.

Firstly, we use lasers to measure chemical reactions, this one could increase resolution and potentially be used to trigger or shape the reaction.

Secondly, it could be a path towards laser-induced fusion which is kind of important.

Finally,, modrrn chips are fabricated using something called an extreme-UV process, that uses sputtered tin hit with a multiple precision laser pulses. This could be used to refine that process further.

[–] [email protected] 1 points 3 days ago

The laws of physics are best understood at standard temperatures and pressures, where we have loads of data. To understand how physics works in more extreme circumstances, we have to create those circumstances and then measure what happens. At CERN, they accelerate particles very fast, smash them together, and record and analyze what happened. This is how they observed the Higgs boson and measured its properties.

From the article, it looks like one of the experiments is to shoot the laser into an oncoming high speed beam of electrons. One of the things they're looking for is if this high amount of energy causes matter and anti matter pairs to spontaneously form and annihilate. Our theories predict this but the more ways we can measure it the more we can learn, for instance about what happened right after the big bang, and why we were left with matter instead of everything annihilating symmetrically.

[–] [email protected] 2 points 3 days ago (1 children)
[–] [email protected] 2 points 2 days ago