this post was submitted on 19 Dec 2023
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[–] [email protected] 13 points 11 months ago (8 children)

I use trig every few years when buying a tv. Tv specs always list diagonal but rarely horizontal and vertical which is needed for knowing how a TV will fit in a space.

[–] [email protected] 13 points 11 months ago (2 children)

I'm trying to figure out how you need trig for that. Just the Pythagorean theorem and ratios seem sufficient to me.

[–] [email protected] 2 points 11 months ago (1 children)

Ratios can be used in trig -- if it's 1.5 times as long as it is tall, tan(\theta) = \frac{2}{3}, which then allows you to find the lengths of the other two sides easily so long as you have a calculator.

[–] [email protected] 2 points 11 months ago (1 children)

Right, but why bring theta into it at all? TV screens are as a hypotenuse (a²+b²) with a fixed ratio (a/b=16/9), so you just need to solve for a and b.

[–] [email protected] 1 points 11 months ago* (last edited 11 months ago) (1 children)

You don't have to, but it seems perfectly easy since you don't have to write anything down to solve it. c*sin(arctan(b/a)) gives b, and c*cos(arctan(b/a)) gives a. I'm not disputing that you can do it without, but I don't think it's necessarily any quicker or easier.

[–] [email protected] 2 points 11 months ago

If it works it works. I just never would have thought to do it that way.

[–] [email protected] 1 points 11 months ago

I am trying to figure out why you'd even need that.
The measurements of the product is usually written in the tech spec.

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