Programmer Humor

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Programmer tries to explain binary search to the police (startrek.website)

submitted 1 year ago by [email protected] to c/[email protected]

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[–] [email protected] 2 points 1 year ago

Yes, I'm aware. But with 12 people you can't simply divvy the groups in threes constantly, because if you weigh and the groups are unequal, then you don't know in which group the different person is (yet). E.g., weighing ABCD - EFGH can tell you the different person is in IJKL if the groups are even, but if they're uneven you don't know in which of the other two groups the different person is.