this post was submitted on 30 Nov 2023
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[–] [email protected] 47 points 1 year ago* (last edited 1 year ago) (17 children)

God damn, whoever came up with that is clever. I would have never come up with that on my own.

[–] [email protected] 55 points 1 year ago* (last edited 1 year ago) (8 children)

Some security camera systems have this built in. They show snapshots of various times where you choose the total period, say 24 hours. Then you glance through the snapshots that are all displayed at once on the screen and click on the last one where your bike was still there. That will then “zoom in” the timeline and show another set of snapshots, though this time within a smaller total time window. Keep clicking on the last panel with the bike, and it will soon show you the clip of the bike being stolen.

Really helpful to find out when something changed.

[–] [email protected] 9 points 1 year ago (2 children)

Yeah, there's no reason it should take an hour no matter how long the tape is.

[–] [email protected] 21 points 1 year ago* (last edited 1 year ago)

If you've got 14 billion years, a theft takes a minute, then you need 53 recursion levels of binary search to find the moment of the theft. (14 billion years can be split into about 7.3e15 1-minute segments, 53 levels of binary search allow you to search through 9e15 segments)

That means OP assumed that it'd take 1 minute to decide whether at a certain still frame the theft had already occured or not, to compute the new offset to seek to, and the time it'd take to actually seek the tape to that point.

Not an unreasonable assumption, but a very conservative estimate. Assuming the footage is on an HDD and you've got an automated system for binary search, I'd actually assume it'd take 5 seconds for each step, meaning finding a 1min theft on 14 billion years of footage would take 5 minutes.

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