this post was submitted on 14 Aug 2023
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[โ€“] [email protected] 2 points 1 year ago (1 children)

Is this a hard error? Like it doesn't compile at all?

Isn't there something like #[allow(unused)] in Rust you can put over the declaration?

[โ€“] [email protected] 1 points 1 year ago

Yes it is a hard error and Go does not compile then. You can do _ = foobar to fake variable usage. I think this is okay for testing purposes.