this post was submitted on 18 Mar 2024
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[–] [email protected] 19 points 8 months ago* (last edited 8 months ago) (10 children)

If a wire were a water stream:

  • Volt is water pressure (fast or slow stream)

  • Ampere how much water there is in the stream

  • Watt is pressure x amount

  • Ohm (resistance) is how much obstructions are in the stream

[–] [email protected] 1 points 8 months ago (8 children)

I never got the pipe analogy. Since liquid water can't be compressed, wouldn't the amperes be directly proportional to the volts and to the size of the pipe, assuming there are no air bubbles? Also, supposedly resistance only reduces current, but when I think of hair in a pipe, the pressure after the obstruction would also be lower (because pressure is directly proportional to the amount of water that flows)

[–] [email protected] 1 points 8 months ago (2 children)

He expressed it wrong. Amperes is diameter of the pipe, how much volume (or charge) can be transferred per unit of length at a given pressure; Watt is the amount of water flowing out at the end, which depends both on pressure and diameter.

[–] [email protected] 1 points 8 months ago* (last edited 8 months ago) (1 children)

Watt is the amount of water flowing out at the end

Shouldn't it instead be the sum of the kinetic energy of all water molecules that come out the other end per unit of time (ie. total amount of energy you use move your volume of water with a certain pressure in a second)?

[–] [email protected] 1 points 8 months ago

Yeah, that's not simple anymore then

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