this post was submitted on 02 Feb 2024
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The fact it's a pointer is part of the type, not part of the variable name. So
int* pis the way.It's part of the type yet it's also a unique identifier. That's the whole thing with east or west
const.const int *is a ~~immutable~~ mutable pointer that points to ~~mutable~~ immutable memory.int *constis a ~~mutable~~ immutable pointer that points to ~~immutable~~ memory.int const *is the same type as the first example, a ~~immutable~~ mutable pointer that points to ~~mutable~~ immutable memory.Same stuff applies to references which makes it easier to think of the variable owning the
*or&as if you want that pointer or reference to beconstit has to go after.Edit:I am a moron who managed to get it exactly backwards :|
Found the guy that can probably do function pointers!
I wrote a couple unholy lines of C++ the other day using the ternary conditional operator to select a class member function to be called with a fixed argument.
I think my teammates were too scared to call me out on it.
KISS, my guy.
It's actually simpler than doing it the "right" way, but I wanted to see how much I could make C++ pretend it was Python.
Lol yeah. I don't even really write C++ but I sure as shit know a bunch of syntax and junk haha
I think you've got it backwards. I learned to read pointer decls from right-to-left, so
const int *is a (mutable) pointer to an int which is const whileint *constis a const pointer to a (mutable) int.Fuck me man that's what I get for writing that just before bed
I always read it right to left and it seems to make sense to me.